1/(t^2-2t-5)^4

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Solution for 1/(t^2-2t-5)^4 equation: 


D( t )

(t^2-(2*t)-5)^4 = 0

(t^2-(2*t)-5)^4 = 0

(t^2-(2*t)-5)^4 = 0

(t^2-2*t-5)^4 = 0

t^2-2*t-5 = 0

t^2-2*t-5 = 0

DELTA = (-2)^2-(-5*1*4)

DELTA = 24

DELTA > 0

t = (24^(1/2)+2)/(1*2) or t = (2-24^(1/2))/(1*2)

t = (2*6^(1/2)+2)/2 or t = (2-2*6^(1/2))/2

(t-((2-2*6^(1/2))/2))*(t-((2*6^(1/2)+2)/2)) = 0

(t-((2-2*6^(1/2))/2))^4*(t-((2*6^(1/2)+2)/2))^4 = 0

( t-((2*6^(1/2)+2)/2) )

t-((2*6^(1/2)+2)/2) = 0 // + (2*6^(1/2)+2)/2

t = (2*6^(1/2)+2)/2

( t-((2-2*6^(1/2))/2) )

t-((2-2*6^(1/2))/2) = 0 // + (2-2*6^(1/2))/2

t = (2-2*6^(1/2))/2

t in (-oo:(2-2*6^(1/2))/2) U ((2-2*6^(1/2))/2:(2*6^(1/2)+2)/2) U ((2*6^(1/2)+2)/2:+oo)

1/((t^2-(2*t)-5)^4) = 0

1/((t^2-2*t-5)^4) = 0

t^2-2*t-5 = 0

t^2-2*t-5 = 0

DELTA = (-2)^2-(-5*1*4)

DELTA = 24

DELTA > 0

t = (24^(1/2)+2)/(1*2) or t = (2-24^(1/2))/(1*2)

t = (2*6^(1/2)+2)/2 or t = (2-2*6^(1/2))/2

(t-((2-2*6^(1/2))/2))*(t-((2*6^(1/2)+2)/2)) = 0

1/((t-((2-2*6^(1/2))/2))^4*(t-((2*6^(1/2)+2)/2))^4) = 0

t belongs to the empty set

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